Sebanyak 200 ml larutan NH4OH 0,4 M dicampur dengan 200 mL larutan HCl 0,2 M Kb=2x10^-5 maka pH campuran yg terjadi adalah.......
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bantu pakai caranya ya
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bantu pakai caranya ya
fatihahalhusna
![\displaystyle [OH^-]=2\times10^{-5}\times\frac{(200\times0,4-200\times0,2)}{200\times0,2}=2\times10^{-5}\ M\\\\pOH=5-\log2\\\\\boxed{\boxed{\bold{pH=9+\log2}}}~~~~(\text{Gak\ ada\ jawaban)}](https://tex.z-dn.net/?f=%5Cdisplaystyle+%5BOH%5E-%5D%3D2%5Ctimes10%5E%7B-5%7D%5Ctimes%5Cfrac%7B%28200%5Ctimes0%2C4-200%5Ctimes0%2C2%29%7D%7B200%5Ctimes0%2C2%7D%3D2%5Ctimes10%5E%7B-5%7D%5C+M%5C%5C%5C%5CpOH%3D5-%5Clog2%5C%5C%5C%5C%5Cboxed%7B%5Cboxed%7B%5Cbold%7BpH%3D9%2B%5Clog2%7D%7D%7D%7E%7E%7E%7E%28%5Ctext%7BGak%5C+ada%5C+jawaban%29%7D "\displaystyle [OH^-]=2\times10^{-5}\times\frac{(200\times0,4-200\times0,2)}{200\times0,2}=2\times10^{-5}\ M\\\\pOH=5-\log2\\\\\boxed{\boxed{\bold{pH=9+\log2}}}~~~~(\text{Gak\ ada\ jawaban)}")
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