Question

Sebanyak 1,8gr glukosa C6H12O6 dilarutkan kedalam 100gr air(ar:c=12 ; h=1;o=16) tentukan molaritas larutan glukosa tersebut

Answer 1

Verified answer

Mr glukosa = 180
ρ air = 1gr/cm^3
ρ = m / v → v = 100/1 = 100 ml
M = gr/Mr * 1000/V
= 1,8/180 * 1000/100
= 0,1 M