Question

Sebanyak 11,7 gram NaCl (Mr=58,5) dilarutkan dalam 100 gram air. jika akb air=0,52 maka tentukan titik didih larutan tersebut

Answer 1

Diket:
mNaCl = 11,7gr
mrNacl = 58,5
massa air = 100gr = 0,1lt
kb air = 0,52
i = 2(karna elektrolit kuat shg nilai i =jumlah ion)
molalitas = (11,7/58,5)/0,1
= 2
delta Tb = Kb x molalitas x i
= 0,52 x 2 x2
= 2,08
delta Tb = Tb larutan - Tb pelarut
2,08 = Tb larutan - 100
102,08 = Tb larutan