Question

Sebanyak 100 ml larutan Ca(OH)2 0.02 m mempunyai pH sbesar ...
A. 2 -log2 B.2-log4 C. 12-log4 D.12-+log4 E.13+log4

Answer 1

OH- = Mb.nb
       = 0,02.2
       = 0,04
       = 4 x 10^-2
       = - Log 4 x 10^-2
pOH= 2- Log 4

pH = 14 - pOH
     = 14 - 2 - Log 4
     = 12 + Log 4

D

   

Answer 2

Ca(OH)2=0,02
[OH-]=M.val=2.10^-2.2=4.10^-2
pOH=-log[OH-]=2-log4
pH=pKw-pOH
   =14-(2-log4)=12+log4