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KOH => K+ + OH-
[OH-] = b × Mb
[OH-] = 1 × 0,02
[OH-] = 2 × 10^(-2)
pOH = - log [OH-]
pOH = - log ( 2 × 10^-2)
pOH = 2 - log 2
pH = 14 - pOH
pH = 14 - (2 - log 2)
pH = 12 + log 2