Sean A y B dos ángulos suplementario, donde A= 8(2x-3)° y B= 10(x+3.5)°. Encuentra la medida del ángulo A.
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8(2x-3)°+10(x+3.5)°= 180°
16x -24°+10x + 35° = 180°
26x + 11°= 180°
26x = 180 -11
26x = 169
x = 169/26
A = 8(2x-3)°
A = 16x - 24
A=104°-24°
A= 80°