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v=przyspieszenie
t=czas
Dane:
s1= 200m
v1=5m/s s(2)=?
Szukane: t(1)= ?(40sek)
s(2)=?
t=s/v t(1)=200/5 t(1)=40sek
v2=0,8m/s
t2=40s
s=v*t s=0,8*40 s=32m
Odp:Lont musi mieć 32metry długośći