Respuesta:
Mm O2 = 32 g/mol
v = 624 L
m = 320 g
T = 27 ºC + 273 = 300 K
n (moles) = 320 g / 32 g/mol = 10 mol
R = 0.082 (L · atm/mol·K)
P · V = n · R · T DESPEJAR P = ?
P = n · R · T / V
P = 10 moles · R = 0.082 (L · atm/mol·K) · 300K / 625 L
P = 0.3936 atm.
1 atm. ------ 760mmHg
0.3936 atm. ------- x
x = 299.136 mmHg
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Verified answer
Respuesta:
Mm O2 = 32 g/mol
v = 624 L
m = 320 g
T = 27 ºC + 273 = 300 K
n (moles) = 320 g / 32 g/mol = 10 mol
R = 0.082 (L · atm/mol·K)
P · V = n · R · T DESPEJAR P = ?
P = n · R · T / V
P = 10 moles · R = 0.082 (L · atm/mol·K) · 300K / 625 L
P = 0.3936 atm.
1 atm. ------ 760mmHg
0.3936 atm. ------- x
x = 299.136 mmHg