Z jakiej wysokości spada ciało, jeżeli uzyskuje prędkość końcową 30 m/s?
z zasady zachowania energii
Ep = Ek
mgh = 0,5mv² => h = v²/2g
v = 30m/s
h = (30m/s)²/2x10m/s² = 45m
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
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z zasady zachowania energii
Ep = Ek
mgh = 0,5mv² => h = v²/2g
v = 30m/s
h = (30m/s)²/2x10m/s² = 45m
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)