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v1 = 0 (Jatuh bebas)
Ek1 = 0
h1 = 28 m
v2 = 20 m/s
g = 10 m/s²
Ditanya:
Ketinggian, h2
Penyelesaian:
Gunakan hukum kekekalan energi mekanik
Em1 = Em2
Ep1 = Ep2 + Ek2
mgh1 = mgh2 + 1/2mv2² (m dicoret)
10*28 = 10*h2 + 1/2*20²
280 = 10h2 + 1/2*400
280 = 10h2 + 200
10h2 = 280 - 200
10h2 = 80
h2 = 80/10
h2 = 8m