Diketahui :
keliling lingkaran 1 (K1) = 75 cm
Ditanya :
keliling lingkaran jika jari jarinya diperbesar 2 kali (K2).
Jawab :
keliling lingkaran 1 = 75 cm, maka,
[tex]\displaystyle\rm K_1 = 2.\pi .r_1[/tex]
[tex] \displaystyle\rm 75 = 2.\pi . r_1 [/tex]
[tex]\displaystyle\rm r _1= \frac{75}{2\pi}[/tex]
jari jari lingkaran 1 = 75/2π, jika diperbesar 2 kalinya maka,
[tex]\displaystyle\rm r_2 = r_1 \times 2[/tex]
[tex]\displaystyle\rm r_2 = \frac{75}{2\pi} \times 2[/tex]
[tex]\displaystyle\rm r_2 = \frac{150}{2\pi} [/tex]
sehingga diperoleh :
[tex] \displaystyle\rm K_2 = 2.\pi . r_2[/tex]
[tex] \displaystyle\rm K_2 = \cancel{2 \pi} ~.~ \frac{150}{\cancel{2\pi}}[/tex]
[tex] \displaystyle\boxed{\bf K_2 =150~cm }[/tex]
Jadi, jawabannya adalah c. 150 cm
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Verified answer
Diketahui :
keliling lingkaran 1 (K1) = 75 cm
Ditanya :
keliling lingkaran jika jari jarinya diperbesar 2 kali (K2).
Jawab :
keliling lingkaran 1 = 75 cm, maka,
[tex]\displaystyle\rm K_1 = 2.\pi .r_1[/tex]
[tex] \displaystyle\rm 75 = 2.\pi . r_1 [/tex]
[tex]\displaystyle\rm r _1= \frac{75}{2\pi}[/tex]
jari jari lingkaran 1 = 75/2π, jika diperbesar 2 kalinya maka,
[tex]\displaystyle\rm r_2 = r_1 \times 2[/tex]
[tex]\displaystyle\rm r_2 = \frac{75}{2\pi} \times 2[/tex]
[tex]\displaystyle\rm r_2 = \frac{150}{2\pi} [/tex]
sehingga diperoleh :
[tex] \displaystyle\rm K_2 = 2.\pi . r_2[/tex]
[tex] \displaystyle\rm K_2 = \cancel{2 \pi} ~.~ \frac{150}{\cancel{2\pi}}[/tex]
[tex] \displaystyle\boxed{\bf K_2 =150~cm }[/tex]
Jadi, jawabannya adalah c. 150 cm