Saya meminta tolong utk menjawab soal no. 6 dibawah ini. trims.
AnnisaFatin
1875 = p × l × t 1875 = 5a × 3a × a a³ = 1875/15 a = 5
p = 5a = 25 m l = 3a = 15 m t = a = 5 m
luas dinding = keliling alas × t = 2(25+15) × 5 = 400 m²
dinding = 4 sisi, tdk termasuk lantai dan langit2
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mahmudah19
Dimisalkan , panj = 5x. lebar = 3x, tinggi = x V = La x tinggi 1875 = 5x . 3x. x 1875 = 15 = 125 = 5 m = x dimasukan , panj = 5. 5 = 25, lebar = 3.5= 15, tinggi = 5 luas dinding (luas selimut) = alas x tinggi = 2 (25 x 5) + 2(15 x 5) = 250 + 150 = 400
1875 = 5a × 3a × a
a³ = 1875/15
a = 5
p = 5a = 25 m
l = 3a = 15 m
t = a = 5 m
luas dinding = keliling alas × t = 2(25+15) × 5 = 400 m²
dinding = 4 sisi, tdk termasuk lantai dan langit2
V = La x tinggi
1875 = 5x . 3x. x
1875 = 15
=
125 =
5 m = x
dimasukan , panj = 5. 5 = 25, lebar = 3.5= 15, tinggi = 5
luas dinding (luas selimut) = alas x tinggi
= 2 (25 x 5) + 2(15 x 5)
= 250 + 150
= 400