Question

Saya mau nanya nih tentang pelajaran matematika aljabar saya. saya mohon dijwb yah 1.(x+2)pangkat2=.... 2.3(2x-1)pangkat3=... 3.2(3p+q)pangkat4=... 4.-3(-x-y)pangkat3=....
5.(4x-2y)pangkat3=....
TERIMAKASIH...

Answer 1

1.(x+2)²
=rumus=1a² + 2ab + 1b²
=1(x)² + 2(x)(2) +1(2)²
=x² + 4x + 4

2.3(2x-1)³
=3 x (2x-1)³
rumus= 1a³ + 3a²b + 3ab² + 1b³
=3 x [1(2x)³ + 3(2x)²(1) + 3(2x)(1)² + 1(1)³]
=3 x [8x³ + 12x² + 6x + 1]
=24x³ + 36x² + 18x + 3

3.2(3p+q)⁴
=2 x (3p+q)⁴
rumus =1a⁴ + 4a³b + 6a²b² + 3ab³ + 1b⁴
=2 x [1(3p)⁴ +4(3p)³(q) +6(3p)²(q)² + 3(3p)(q)³ +1(q)⁴]
=2 x [81p⁴ + 96p³q + 54p²q² + 9pq³ + q⁴]
=162p⁴ + 192p³q + 108p²q² + 18pq³ + q⁴

4.(-3)(-x-y)³
=(-3) x (-x-y)³
rumus=1a³ + 3a²b + 3ab² + 1b³
=(-3) x [1(-x)³ + 3(-x)²(-y) + 3(-x)(-y)² + (-y)³]
=(-3) x [(-x³) + 3(x²)(-y) + 3(-x)(y²) - y³
=(-3) x [-x³ - 3x²y - 3xy² -y³]
=3x³ +9x²y + 9xy² +3y³

5.(4x-2y)³
rumus=1a³ + 3a²b + 3ab² + 1b³
=1(4x)³ + 3(4x)²(-2y) + 3(4x)(-2y)² + 1(-2y)³
=64x - 96x²y + 48xy² - 8y³