R.T de un ángulo en posición normal.
sen = y/r
cos = x/r
tan = y/x
cot = x/y
sec = r/x
csc = r/y
r = √x²+y²
Respuesta:
( x;y ) = ( -7;-24 )
r = √(-7) + (-24)
r = √49 + 576
r = √625
r = 25
Senα · Cscα
( -24/25 ) · ( 25/-24 )
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Verified answer
R.T de un ángulo en posición normal.
sen = y/r
cos = x/r
tan = y/x
cot = x/y
sec = r/x
csc = r/y
r = √x²+y²
Respuesta:
( x;y ) = ( -7;-24 )
r = √(-7) + (-24)
r = √49 + 576
r = √625
r = 25
Senα · Cscα
( -24/25 ) · ( 25/-24 )
1