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dan (2x-3) adlah faktor --> 2x-3 = 0 ---> x= 3/2
sub ke f(x) = 0
f(3/2) = (a+1)(3/2)^3 + (3/2)^2 - (3/2) + 3 = 0
27/8 (a+1) + 9/4 - 3/2 + 3= 0
27/8 (a+1) +15/4 = 0
27/ 8 (a+1) = 15/4
a+1 = 15/4 : 27/8 = 10/9
a = 10/9 - 1
a= 1/9