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=> 2y + 3 = 0
2y = -3
y = -3/2
atau
=> 4y - 5 = 0
4y = 5
y = 5/4
(2y + 3) (4y - 5)
2y + 3 = 0
2y = -3
y = -3/2
4y - 5 = 0
4y = 5
y = 5/4
HP : {-3/2 ; 5/4}