Question

Sajikan dalam bentuk x^ay^bz^c! (soal pada gambar)

Answer 1

A) (x²y^(-1/3))(x^(-7/6) y^(-1/2)) / (x^(-1/12) y^(1/2))(x^(-1/4)y^(2/3))
= (x^(5/6) y^(-5/6)) / (x^(-1/3) y ^(7/6))
= x^(5/6 - (-1/3)) y^(-5/6 - 7/6)
= x^(1/2) y^(-2)
= (√x)/y²

b) (x^(1/3) y^(2/3) z)(x⁻²y^(1/3)z^(-2/3)) / (x^(-2/3) y^(2/9) z²)
= x^(1/3 - 2 - 2/3) y^(2/3 + 1/3 - 2/9) z^(1 - 2/3 - 2)
= x⁻³ y^(-2/9) z^(-5/3)

keterangan:
^ = pangkat