hay que recordar
sec (x)=1/cos(x)
cos(x)=1/sec (x)
sen(3x) *sec (12x)=1
sen(3x) =[tex]\frac{1}{sec (12x)}[/tex]
[tex]\frac{1}{sec (12x)}[/tex]=cos(y) y=12x
sen 3x=cos 12x
sen x=cos y
x+y=90
entonces
12x+3x=90
15x=90
x=6
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hay que recordar
sec (x)=1/cos(x)
cos(x)=1/sec (x)
sen(3x) *sec (12x)=1
sen(3x) *sec (12x)=1
sen(3x) =[tex]\frac{1}{sec (12x)}[/tex]
[tex]\frac{1}{sec (12x)}[/tex]=cos(y) y=12x
sen 3x=cos 12x
hay que recordar
sen x=cos y
x+y=90
entonces
12x+3x=90
15x=90
x=6