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- kapilaritas
d = 0,6 mm → r = 0,3 mm = 3×10⁻⁴ m
γ = 72,8×10⁻³ N/m
ρ = 10³ kg/m³
g = 9,8 m/s²
θ = ??? anggap 0°
h =___ ?
kenaikan permukaan air di dalam pipa kapiler
2 γ cos θ
h = -------------
ρ g r
2 (72,8×10⁻³ N/m) (1)
h = --------------------------------------------------
(10³ kg/m³) (9,8 m/s²) (3×10⁻⁴ m)
h = 0,0495 m ← jawaban