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diketahui :m=2kg
v=20m/s
ditanya : Ek=........?
dijawab : Ek=1/2.m.vpangkat 2
Ek=1/2×2kg×(20m/s)pangkat2
Ek=1/2×2kg×20m/s×20m/s
Ek=1/2×800 j= 400 joule
b)energi potensiAl
diketahui:m=2kg
h=10m
g=10m/s2
ditanya :Ep=........?
dijawab :Ep=m.g.h
Ep=2kg×10m×10m/s2
Ep=200 joule
c)energi mekanik
diketahui:Ek=400joule
Ep=200joule
ditanya : Em=........?
dijawab : Em=Ep+Ek
Em=200 j + 400 j =600 j