Sebuah benda diberi gaya 30 N, benda akan bergerak dgn percepatan 5 m/s2. besar gaya yg dibutuhkan agar benda tsb bergerak dg percepatan 2m/s2 adalah.....
baiqdwikencana
F=m.a 30=m.5 m=30/5 = 6 jadi F=m.a =6.2 = 12 N
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ansheillat
Diketahui = F1 = 30 N a1 = 5 m/s ^2 a2 = 2 m/s^2 m1=m2 Ditanya = F2 ? Jawab = F1/F2 = (m1.a1)/(m2.a2) 30/F2 = (m1.5)/(m1.2) .......#m1 dicoret 30/F2= 5/2 F2 = 12 N
30=m.5
m=30/5 = 6
jadi F=m.a
=6.2 = 12 N
a1 = 5 m/s ^2
a2 = 2 m/s^2
m1=m2
Ditanya = F2 ?
Jawab = F1/F2 = (m1.a1)/(m2.a2)
30/F2 = (m1.5)/(m1.2) .......#m1 dicoret
30/F2= 5/2
F2 = 12 N