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dane: v1=340m/s, v2=8000m/s, dt=0,1s
szukane: x-długość stalowej rury
dt = t1-t2.......t1 = x/v1.......t2=x/v2......./s=vt...v=s/t......t=s/v/
dt = x/v1 - x/v2 = x*[1/v1 - 1/v2] = x*[v2-v1]/v1*v2
x = dt*v1*v2 //[v2-v1] = 0,1s *340m/s*8000m/s //7660m/s = 35,51m.
Odp.: Długość rury wynosiła 35,51 m.
...........................pozdrawiam