[tex]Dane:\\F_1 = F_2 = F\\m_1 = 4 \ kg\\a_1 = 2\frac{m}{s^{2}}\\m_2 = 16 \ kg\\Szukane:\\a_2 = ?\\\\Rozwiazanie\\\\Z \ II \ zsady \ dynamiki \ Newtona:\\\\a = \frac{F}{m} \ \ \rightarrow \ \ F = m\cdot a\\\\F = m_1\cdot a_1 = 4 \ kg\cdot \ 2\frac{m}{s^{2}} = 8 \ N\\\\a_2 = \frac{F}{m_2} = \frac{8 \ N}{16 \ kg} =\frac{8 \ kg\cdot\frac{m}{s^{2}}}{16 \ kg}=\boxed{0,5\frac{m}{s^{2}}}[/tex]
Odp. Ciałao o masie 16 kg będzie się poruszało z przyspieszeniem 0,5 m/s².
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[tex]Dane:\\F_1 = F_2 = F\\m_1 = 4 \ kg\\a_1 = 2\frac{m}{s^{2}}\\m_2 = 16 \ kg\\Szukane:\\a_2 = ?\\\\Rozwiazanie\\\\Z \ II \ zsady \ dynamiki \ Newtona:\\\\a = \frac{F}{m} \ \ \rightarrow \ \ F = m\cdot a\\\\F = m_1\cdot a_1 = 4 \ kg\cdot \ 2\frac{m}{s^{2}} = 8 \ N\\\\a_2 = \frac{F}{m_2} = \frac{8 \ N}{16 \ kg} =\frac{8 \ kg\cdot\frac{m}{s^{2}}}{16 \ kg}=\boxed{0,5\frac{m}{s^{2}}}[/tex]
Odp. Ciałao o masie 16 kg będzie się poruszało z przyspieszeniem 0,5 m/s².