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h = [ ( Vo ) ² Sen²( x ) ] / 2g
h = [ ( 14 m/s )²Sen²( 30 ) ] / 2( 9.8 m/s² )
h = 5/2 m = 2.50 m
El alcance máximo esta dado por:
x = [ ( Vo ) ² Sen( 2x ) ] / g
x = [ ( 14 m/s )²Sen( 60 ) ] / ( 9.8 m/s² )
x = 17.32 m
Espero haberte ayudado, saludos!