Mobil P dan Q sedang bergerak. Massa mobil P sama dengan masa mobil Q. Mobil P memiliki energi kinetik 40.000 J, mobil Q memiliki energi kinetik 9 kali mobil P. Jika kecepatan mobil P 10m/s .maka keceatan mobil Q adalah ...
a. 5 m/s
b. 10 m/s
c. 15 m/s
d. 30 m/s
* tolong pake caranya ya , buat besok ujian nieh ..
a. 5 m/s
b. 10 m/s
c. 15 m/s
d. 30 m/s
* tolong pake caranya ya , buat besok ujian nieh ..
izharulhaq78
![E_{k}P=a \\ E_kQ=9(E_kP)=9a \\ v_P=10m/s \\ \\ v_Q=? \\ \\ \frac{E_kP}{E_kQ}= \frac{ \frac{mv_P^2}{2} }{ \frac{mv_Q^2}{2}} \\ \frac{E_kP}{E_kQ}= \frac{v_P^2}{v_Q^2} \\ \frac{a}{9a}= \frac{v_P^2}{v_Q^2} \\ \frac{1}{9}= \frac{v_P^2}{v_Q^2} \\ \frac{ \sqrt{1} }{ \sqrt{9} }= \frac{v_P}{v_Q} \\ \frac{1}{3}= \frac{10}{v_Q} \\ v_Q=3(10) \\ v_Q=30m/s[D]](https://tex.z-dn.net/?f=E_%7Bk%7DP%3Da+%5C%5C+E_kQ%3D9%28E_kP%29%3D9a+%5C%5C+v_P%3D10m%2Fs+%5C%5C++%5C%5C+v_Q%3D%3F+%5C%5C++%5C%5C++%5Cfrac%7BE_kP%7D%7BE_kQ%7D%3D+%5Cfrac%7B+%5Cfrac%7Bmv_P%5E2%7D%7B2%7D+%7D%7B+%5Cfrac%7Bmv_Q%5E2%7D%7B2%7D%7D+%5C%5C+%5Cfrac%7BE_kP%7D%7BE_kQ%7D%3D+%5Cfrac%7Bv_P%5E2%7D%7Bv_Q%5E2%7D+%5C%5C+%5Cfrac%7Ba%7D%7B9a%7D%3D+%5Cfrac%7Bv_P%5E2%7D%7Bv_Q%5E2%7D+%5C%5C+%5Cfrac%7B1%7D%7B9%7D%3D+%5Cfrac%7Bv_P%5E2%7D%7Bv_Q%5E2%7D+%5C%5C++%5Cfrac%7B+%5Csqrt%7B1%7D+%7D%7B+%5Csqrt%7B9%7D+%7D%3D+%5Cfrac%7Bv_P%7D%7Bv_Q%7D+%5C%5C++%5Cfrac%7B1%7D%7B3%7D%3D+%5Cfrac%7B10%7D%7Bv_Q%7D+%5C%5C+v_Q%3D3%2810%29+%5C%5C+v_Q%3D30m%2Fs%5BD%5D "E_{k}P=a \\ E_kQ=9(E_kP)=9a \\ v_P=10m/s \\ \\ v_Q=? \\ \\ \frac{E_kP}{E_kQ}= \frac{ \frac{mv_P^2}{2} }{ \frac{mv_Q^2}{2}} \\ \frac{E_kP}{E_kQ}= \frac{v_P^2}{v_Q^2} \\ \frac{a}{9a}= \frac{v_P^2}{v_Q^2} \\ \frac{1}{9}= \frac{v_P^2}{v_Q^2} \\ \frac{ \sqrt{1} }{ \sqrt{9} }= \frac{v_P}{v_Q} \\ \frac{1}{3}= \frac{10}{v_Q} \\ v_Q=3(10) \\ v_Q=30m/s[D]")
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Thanks 1
Eristaa07
40.000 J nya gak dipake ?
izharulhaq78
itu diganti dengan a
Eristaa07
okk ... thanks