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v1 = 40m/s
v2 = 20 m/s
α = 60°
ditanya:
v1-v2 =?
jawab:
v1-v2 = √v1²+v2²-2v1v2 cosα
v1-v2 = √40²+20²-2(40)(20)cos60
v1-v2 = √1600+400 - 800
v1-v2 = √1200
vi-v2 = 20√3 m/s