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s = 1.400 m
V1 = 20 m/s
V2 = 15 m/s
maka :
t = s/(V1+V2)
= 1.400 / 20+15
= 1.400 / 35
= 40 sekon
jadi meka bertemu pada detik ke 40
= v1= 20 m/s
=v2= 15 m/s
ditanya= t......?
jawab = t = s/v1+v2
= 1400/20+15
=1400/35
=40 sekon