Piechur idzie ze stałą predkoscia v=1,2m/s. jaka droge przeberdzie w czasie 0.5 h ?
Dane:V = 1,2m/st = 0,5h = 30min. = 1 800sSzukane:s = ?s = V × ts = 1,2m/s × 1 800ss = 2160mOdp: Piechur w czasie 0,5h przebędzie 2160m.
s+v(razy)t
s= 1,2 m/s
t= 0,5h=30 min= 1800s
s= 1,2 m/s(razy) 1800s=2160m
odp. droga to 2160 m
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Dane:
V = 1,2m/s
t = 0,5h = 30min. = 1 800s
Szukane:
s = ?
s = V × t
s = 1,2m/s × 1 800s
s = 2160m
Odp: Piechur w czasie 0,5h przebędzie 2160m.
s+v(razy)t
s= 1,2 m/s
t= 0,5h=30 min= 1800s
s= 1,2 m/s(razy) 1800s=2160m
odp. droga to 2160 m