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vi = 15 m/s
vf = 40 m/s
t = 6s
a = ?
Calculamos la aceleración.
a = (vf - vi)/t
a = (40 m/s - 15 m/s)/6s
a = (25 m/s)/6s
a = 4,16 m/s²
La aceleración de la moto es 4,17 m/s²
datos
vf= 40m/s
vi=15m/s
t= 6s
sustituimos
(40m/s - 15m/s)/6s
(25m/s)/6s= 4.6m/s^2