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Voy = (60 m/s)(cos 30°) = 51.9615 m/s
En Y: -g = -9.8 m/s² (Tiro Vertical)
Vfy² = Voy² - 2gH
Vfy² = 0
Voy² = 2gH
(51.9615 m/s)² = 2(9.8 m/s²)H
H = [(51.9615 m/s)²/(2(9.8 m/s²))]
Hmax = 137.755 metros
Tiempo en alcanzar la altura maxima
Vfy = Voy - gT
Vfy = 0
Voy = gt
t = (Voy)/(g)
t = (51.9615 m/s)/(9.8 m/s²)
t = 5.3022 seg
Tiempo en el aire es 2 veces el tiempo en alcanzar la altura maxima
Tiempo en el aire = 2(5.3022 seg) = 10.6044 seg
En X: Movimiento Uniforme
Dx = Vox*(t)
Dx = (30 m/s)(10.6044 seg)
Dx = 318.132 metros
Distancia alcanzada = 318.132 metros