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V0 = 70.2k/h convirtiendo a m/s qudaria = 19.5m/s
a = -3m/s2
vf = 0
d = ?
Solucion :
Formula : Vf al cuadrado = V0 al cuadrado + 2ad (aceleracion por distancia )
remplazamos valores :
0 al cuadrado = 19.5 al cuadrado + 2(-3)*d
0= 380.25 + 2(-3)*d
380*25= -6*d
380*25/-6 = d
-63.37m = d
El auto recorre 63.37m hasta detenerse