Odpowiedź:
I Omega I = 6³ = 216
A = { (1,1,1),(112),(121),(211)}
I A I = 4
P( A ) = [tex]\frac{4}{216} = \frac{1}{54}[/tex]
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Szczegółowe wyjaśnienie:
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Odpowiedź:
I Omega I = 6³ = 216
A = { (1,1,1),(112),(121),(211)}
I A I = 4
P( A ) = [tex]\frac{4}{216} = \frac{1}{54}[/tex]
================
Szczegółowe wyjaśnienie: