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substitusikan a ke pers tersebut maka nanti didapat n (banyak suku)
2Sn = n(2a + bn - b)
2Sn = 2an + bn^2 - bn
2Sn = bn^2 - (2a - b)n
bn^2 - (2a-b)n - 2Sn = 0
n = (( 2a - b) + √((-2a-b)^2 +8Sn) ) / 2
atau
n =(( 2a - b) - √((-2a-b)^2 +8Sn) ) / 2