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f(3) = 15
f(3) = 3a + b = 15
f(5) = 5a + b = 20
dieleminasi (dikurang)
f(5)-f(3)
2a = 5
a = 5/2
substitusi
f(3) = 3a + b = 15
f(3) = 3 (5/2) + b = 15
f(3) = 15/2 + b = 15 (kali 2 semua)
15+2b = 30
2b = 15
b = 15/2
b)
f(x) Ax + b
f(x) = 5/2 x + 15/2
c) f(-2) = 5/2 kali -2 + 15/2
f(-2) = -5+15/2 (jadikan per 2 semua)
f(-2 ) = -10/2 + 15/2
f(-2) = 5/2