Odpowiedź:
[tex]x_1 = - 2[/tex] [tex]x_2 = 1[/tex]
więc
( x + 2)*(x - 1) = x² + b x + c
x² - x +2 x - 2 = x² + b x + c
x² + x - 2 = x² + b x + c
zatem b = 1 c = - 2
2 b + c = 2*1 - 2 = 2 - 2 = 0
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Odpowiedź:
[tex]x_1 = - 2[/tex] [tex]x_2 = 1[/tex]
więc
( x + 2)*(x - 1) = x² + b x + c
x² - x +2 x - 2 = x² + b x + c
x² + x - 2 = x² + b x + c
zatem b = 1 c = - 2
2 b + c = 2*1 - 2 = 2 - 2 = 0
=======================
Szczegółowe wyjaśnienie: