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n=c*v=0.1mol/dm3*0.1dm3=0.01mola
(ii)
CuSO4 + Mg ---> MgSO4 + Cu
z reakcji wynika że z :
1 mola CuSO4 otrzymujemy 1mol Cu
to z 0,01mola --------- x
x=0.01*1/1=0,01mola
1mol Cu to 63.5g
0.01 ---- x
x=0.01*63.5/1=0.635g