Odpowiedź:
Szczegółowe wyjaśnienie:
a.
[tex]\frac{2}{x} =\frac{3}{x-1}[/tex]
D: x≠0 x-1≠0
x≠1
D=R/{0, 1}
[tex]2(x-1)=3x\\2x-2=3x\\x=-2[/tex]∈D
b.
[tex]\frac{4}{x+1} =\frac{5}{x}[/tex]
D: x+1≠0 x≠0
x≠-1
D=R/{-1, 0}
[tex]4x=5(x+1)\\4x=5x+5\\x=-5[/tex]∈D
d.
[tex]\frac{2x+1}{1-2x} =\frac{2}{3}[/tex]
D: 1-2x≠0
2x≠1
x≠1/2
D=R/{[tex]\frac{1}{2}[/tex]}
3(2x+1)=2(1-2x)
6x+3=2-4x
10x=-1
x=[tex]-\frac{1}{10}[/tex] ∈D
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
Odpowiedź:
Szczegółowe wyjaśnienie:
a.
[tex]\frac{2}{x} =\frac{3}{x-1}[/tex]
D: x≠0 x-1≠0
x≠1
D=R/{0, 1}
[tex]2(x-1)=3x\\2x-2=3x\\x=-2[/tex]∈D
b.
[tex]\frac{4}{x+1} =\frac{5}{x}[/tex]
D: x+1≠0 x≠0
x≠-1
D=R/{-1, 0}
[tex]4x=5(x+1)\\4x=5x+5\\x=-5[/tex]∈D
d.
[tex]\frac{2x+1}{1-2x} =\frac{2}{3}[/tex]
D: 1-2x≠0
2x≠1
x≠1/2
D=R/{[tex]\frac{1}{2}[/tex]}
3(2x+1)=2(1-2x)
6x+3=2-4x
10x=-1
x=[tex]-\frac{1}{10}[/tex] ∈D