Odpowiedź: Mam nadzieję że pomogłem ;)
a ) 3 x - 5 < 1 1 - 2 x ≤ 3
3 x < 6 / : 3 -2 x ≤ 2 / : ( - 2)
x < 2 x ≥ - 1
A = ( - ∞ ; 2 ) B = < - 1 ; + ∞ )
A ∩ B = < - 1 ; 2 ) A \ B = ( - ∞ ; - 1 )
b)
2 - 5 x < 1 - 2 x 1/2x+0,75<1 | * 2 (mnożyć*)
-3 x < - 1 / : ( - 3) x + 1,5 < 2
x > 1/3 x < 0,5 = 1/2
A = ( 1/3; + ∞ ) B = ( -∞ ; 1/2 )
A ∩ B = ( 1/3;1/2) A \ B = < 1/2 + ∞ )
c ) - 4 < 2 x ≤ 6 / : 2 1 ≤ 3 x + 1 < 7 / -1
- 2 < x ≤ 3 0 ≤ 3 x < 6 / : 3
A = ( - 2 ; 3 > 0 ≤ x < 2 B = < 0 ; 2 )
A ∩ B = < 0 ; 2 ) = B A \ B = ( - 3 ; 0 ) ∪ < 2 ; 3 >
d )
- 3 ≤ 2 - x ≤ 3 / - 2 0 < 1 - 2 x ≤ 5 / - 1
- 5 ≤ - x ≤ 1 / ( - 1) - 1 < -2 x ≤ 4 / : ( - 2)
5 ≥ x ≥ - 1 1/2 > x ≥ - 2
- 1 ≤ x ≤ 5 - 2 ≤ x < 1/2
A = < - 1 ; 5 > B = < - 2 ; 1/2 )
A ∩ B = < - 1 ; 1/2 ) A \ B = <1/2;5 >
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Odpowiedź: Mam nadzieję że pomogłem ;)
a ) 3 x - 5 < 1 1 - 2 x ≤ 3
3 x < 6 / : 3 -2 x ≤ 2 / : ( - 2)
x < 2 x ≥ - 1
A = ( - ∞ ; 2 ) B = < - 1 ; + ∞ )
A ∩ B = < - 1 ; 2 ) A \ B = ( - ∞ ; - 1 )
b)
2 - 5 x < 1 - 2 x 1/2x+0,75<1 | * 2 (mnożyć*)
-3 x < - 1 / : ( - 3) x + 1,5 < 2
x > 1/3 x < 0,5 = 1/2
A = ( 1/3; + ∞ ) B = ( -∞ ; 1/2 )
A ∩ B = ( 1/3;1/2) A \ B = < 1/2 + ∞ )
c ) - 4 < 2 x ≤ 6 / : 2 1 ≤ 3 x + 1 < 7 / -1
- 2 < x ≤ 3 0 ≤ 3 x < 6 / : 3
A = ( - 2 ; 3 > 0 ≤ x < 2 B = < 0 ; 2 )
A ∩ B = < 0 ; 2 ) = B A \ B = ( - 3 ; 0 ) ∪ < 2 ; 3 >
d )
- 3 ≤ 2 - x ≤ 3 / - 2 0 < 1 - 2 x ≤ 5 / - 1
- 5 ≤ - x ≤ 1 / ( - 1) - 1 < -2 x ≤ 4 / : ( - 2)
5 ≥ x ≥ - 1 1/2 > x ≥ - 2
- 1 ≤ x ≤ 5 - 2 ≤ x < 1/2
A = < - 1 ; 5 > B = < - 2 ; 1/2 )
A ∩ B = < - 1 ; 1/2 ) A \ B = <1/2;5 >