Jaki dział i temat bo bez tego tak średnio.
[tex]y = x+1\\y = x^{2}-1\\\\x^{2}-1 = x+1\\\\x^{2}-x-1-1 = 0\\\\x^{2}-x-2 = 0\\\\a = 1, \ b = -1, \ c = -2\\\\\Delta = b^{2}-4ac = (-1)^{2}-4\cdot1\cdot(-2) = 1+8 = 9\\\\\sqrt{\Delta} = \sqrt{9} = 3\\\\x_1 = \frac{-b-\sqrt{\Delta}}{2a} = \frac{1-3}{2\cdot1} = \frac{-2}{2} = -1\\\\x_2 = \frac{-b+\sqrt{\Delta}}{2a} = \frac{1+3}{2} = \frac{4}{2} = 2[/tex]
[tex]y_1 = -1+1 = 0\\\\y_2 = 2^{2}-1 = 4-1 = 3[/tex]
{x₁ = -1
{y₁ = 0
{x₂ = 2
{y₂ = 3
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Jaki dział i temat bo bez tego tak średnio.
[tex]y = x+1\\y = x^{2}-1\\\\x^{2}-1 = x+1\\\\x^{2}-x-1-1 = 0\\\\x^{2}-x-2 = 0\\\\a = 1, \ b = -1, \ c = -2\\\\\Delta = b^{2}-4ac = (-1)^{2}-4\cdot1\cdot(-2) = 1+8 = 9\\\\\sqrt{\Delta} = \sqrt{9} = 3\\\\x_1 = \frac{-b-\sqrt{\Delta}}{2a} = \frac{1-3}{2\cdot1} = \frac{-2}{2} = -1\\\\x_2 = \frac{-b+\sqrt{\Delta}}{2a} = \frac{1+3}{2} = \frac{4}{2} = 2[/tex]
[tex]y_1 = -1+1 = 0\\\\y_2 = 2^{2}-1 = 4-1 = 3[/tex]
{x₁ = -1
{y₁ = 0
{x₂ = 2
{y₂ = 3