[tex]\left\{\begin{array}{l}\frac{2x-y}{5}-\frac{y+2x}{4}=1,2\\\frac{2x+3y}{12}-\frac{4x-y}{8}=0,25\end{array}\right.\\\\\left\{\begin{array}{l}\frac{2x-y}{5}-\frac{y+2x}{4}=\frac{12}{10}\ |*20\\\frac{2x+3y}{12}-\frac{4x-y}{8}=\frac{1}{4}\ |*24\end{array}\right.\\\\\left\{\begin{array}{l}4(2x-y)-5(y+2x)=24\\2(2x+3y)-3(4x-y)=6\end{array}\right.\\\\\left\{\begin{array}{l}8x-4y-5y-10x=24\\4x+6y-12x+3y=6\end{array}\right.\\\\\left\{\begin{array}{l}-2x-9y=24\\-8x+9y=6\end{array}\right|+[/tex]
[tex]\left\{\begin{array}{l}-10x=30\ |:(-10)\\-8x+9y=6\end{array}\right.\\\\\left\{\begin{array}{l}x=-3\\-8*(-3)+9y=6\end{array}\right.\\\\\left\{\begin{array}{l}x=-3\\24+9y=6\end{array}\right.\\\\\left\{\begin{array}{l}x=-3\\9y=-18\ |:9\end{array}\right.\\\\\left\{\begin{array}{l}x=-3\\y=-2\end{array}\right.[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
[tex]\left\{\begin{array}{l}\frac{2x-y}{5}-\frac{y+2x}{4}=1,2\\\frac{2x+3y}{12}-\frac{4x-y}{8}=0,25\end{array}\right.\\\\\left\{\begin{array}{l}\frac{2x-y}{5}-\frac{y+2x}{4}=\frac{12}{10}\ |*20\\\frac{2x+3y}{12}-\frac{4x-y}{8}=\frac{1}{4}\ |*24\end{array}\right.\\\\\left\{\begin{array}{l}4(2x-y)-5(y+2x)=24\\2(2x+3y)-3(4x-y)=6\end{array}\right.\\\\\left\{\begin{array}{l}8x-4y-5y-10x=24\\4x+6y-12x+3y=6\end{array}\right.\\\\\left\{\begin{array}{l}-2x-9y=24\\-8x+9y=6\end{array}\right|+[/tex]
[tex]\left\{\begin{array}{l}-10x=30\ |:(-10)\\-8x+9y=6\end{array}\right.\\\\\left\{\begin{array}{l}x=-3\\-8*(-3)+9y=6\end{array}\right.\\\\\left\{\begin{array}{l}x=-3\\24+9y=6\end{array}\right.\\\\\left\{\begin{array}{l}x=-3\\9y=-18\ |:9\end{array}\right.\\\\\left\{\begin{array}{l}x=-3\\y=-2\end{array}\right.[/tex]