Odpowiedź:
a) x²-4≠0 D=R\{-2,2}
x(x+2)/(x-2)(x+2)=0
x/(x-2)= 0 x=0
b) D=R a=1 b=6 c=-16
Δ=b²-4ac= 36+ 64=100 x1=(-b-√Δ)/2a=(-6-10)/2=-8
x2=(-b+√Δ)/2a=( -6+10)/2=2
c) D=R
Δ=16+20=36 x1= ( 4-6)/2=-1 x2=(4+6)/2=5
(x+2√2)(x-2√2)(x+1)(x-5)
x={ -2√2,-1,2√2,5}
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Verified answer
Odpowiedź:
a) x²-4≠0 D=R\{-2,2}
x(x+2)/(x-2)(x+2)=0
x/(x-2)= 0 x=0
b) D=R a=1 b=6 c=-16
Δ=b²-4ac= 36+ 64=100 x1=(-b-√Δ)/2a=(-6-10)/2=-8
x2=(-b+√Δ)/2a=( -6+10)/2=2
c) D=R
Δ=16+20=36 x1= ( 4-6)/2=-1 x2=(4+6)/2=5
(x+2√2)(x-2√2)(x+1)(x-5)
x={ -2√2,-1,2√2,5}
Szczegółowe wyjaśnienie: