[tex]2x-3=4-\frac{x-1}{2}\,|\cdot2\\\\4x-6=8-(x-1)\\4x-6=8-x+1\\4x+x=8+6+1\\5x=15\,|\div5\\\boxed{x=3}[/tex]
Odpowiedź:
2x-3 = 4 - x-1/2 /*2
4x -6 = 8-(x-1)
4x-6= 8 -(x-1)
4x-6 =8-x+1
4x+x=8+1+6
5x= 15 /:5
x= 3
Szczegółowe wyjaśnienie:
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[tex]2x-3=4-\frac{x-1}{2}\,|\cdot2\\\\4x-6=8-(x-1)\\4x-6=8-x+1\\4x+x=8+6+1\\5x=15\,|\div5\\\boxed{x=3}[/tex]
Odpowiedź:
2x-3 = 4 - x-1/2 /*2
4x -6 = 8-(x-1)
4x-6= 8 -(x-1)
4x-6 =8-x+1
4x+x=8+1+6
5x= 15 /:5
x= 3
Szczegółowe wyjaśnienie: