Question

Rozwiąż równanie: 3sinx+cos2x-sinx=1

Answer 1

Odpowiedź:

cos(2 x) + 2 sin(x) = 1

1 + 2 sin(x) - 2 sin^2(x) = 1

-1/2 - sin(x) + sin^2(x) = -1/2

sin^2(x) - sin(x) = 0

sin(x) (sin(x) - 1) = 0

sin(x) - 1 = 0 lub sin(x) = 0

sin(x) = 1 lub sin(x) = 0

x = 2 π n1 + π/2 lub  sin(x) = 0

sin(x) = 0

x = π n2 dla x Z i n2

x = π n2 dla π n2 ∈ Z