Dane:
P = moc = 2,6 kW = 2600W [kilo = 1000]
U = napięcie = 12 V
Użyjemy wzoru na moc i skorzystamy z prawa Ohma
P = U · I oraz R = ⇒ I =
P = U · = ⇒ R = = ≈ 0,055Ω
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Dane:
P = moc = 2,6 kW = 2600W [kilo = 1000]
U = napięcie = 12 V
Użyjemy wzoru na moc i skorzystamy z prawa Ohma
P = U · I oraz R = ⇒ I =
P = U · = ⇒ R = = ≈ 0,055Ω