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100cm³ wody ma masę 100g bo d=1g/cm³
mr = 100g+10g = 110g
ms = 10g
cp = ms*100%/mr
cp = 10g*100%/110g = 9,09%
ms (masa substancji) = 10 gramów
mr (masa roztworu) = ms (masa substancji) + mw (masa wody) = 10 g +100 cm3 = 110 gram
a więc: cp = 10g x 100% / 110 g = 9,1%
odp. Stężenie procentowe otrzymanego roztworu wynosi 9,1%.