rozcienczono woda 0,5dm3 1-molowego roztworu CuSO4.ile cm3 0,3-molowego roztworu otrzymano?
V=0,5dm3 + H20------------------------- cm=0,3 mol/dm3
cm=1 mol/dm3 cm= n/V
V= 0,5 dm3 V= n:cm
cm=n/V V=0,5 :0,3
n=cm*V V= 1,7 dm3
n=0,5 *1
n=0,5 mola= constance
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V=0,5dm3 + H20------------------------- cm=0,3 mol/dm3
cm=1 mol/dm3 cm= n/V
V= 0,5 dm3 V= n:cm
cm=n/V V=0,5 :0,3
n=cm*V V= 1,7 dm3
n=0,5 *1
n=0,5 mola= constance