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R-100= P/2 (2)
Reemplazas (1) en (2)
3P - 100= P/2
2×3P - 2×100= P
6P - 200= P
6P- P = 200
5P = 200
P = 200/5
P = 40
Reemplazas P en (1)
R = 3P
R = 3×40
R = 120
RESPUESTA ES
RICARDO tiene 120 y Pablo 40