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![$\begin{align} \frac{2p}{q}&= \sqrt[3]{p^3q^6}~:~ \sqrt{(pq)^2} \end{align}](https://tex.z-dn.net/?f=%24%5Cbegin%7Balign%7D+%5Cfrac%7B2p%7D%7Bq%7D%26%3D+%5Csqrt%5B3%5D%7Bp%5E3q%5E6%7D%7E%3A%7E+%5Csqrt%7B%28pq%29%5E2%7D+%5Cend%7Balign%7D "$\begin{align} \frac{2p}{q}&= \sqrt[3]{p^3q^6}~:~ \sqrt{(pq)^2} \end{align}")
RonaldRobi
![\displaystyle 1.) \frac{2p}{q} = \sqrt[3]{p^3q^6} : \sqrt{(pq)^2} \\ \frac{2p}{q} = pq^2 : pq \\ \frac{2p}{q} = q \\ 2p = q^2 \\ p = \frac{q^2}{2} \ \text{atau} \ q = \sqrt{2p}](https://tex.z-dn.net/?f=%5Cdisplaystyle+1.%29+%5Cfrac%7B2p%7D%7Bq%7D+%3D++%5Csqrt%5B3%5D%7Bp%5E3q%5E6%7D+%3A++%5Csqrt%7B%28pq%29%5E2%7D++%5C%5C++%5Cfrac%7B2p%7D%7Bq%7D+%3D+pq%5E2+%3A+pq+%5C%5C++%5Cfrac%7B2p%7D%7Bq%7D+%3D+q+%5C%5C+2p+%3D+q%5E2+%5C%5C+p+%3D++%5Cfrac%7Bq%5E2%7D%7B2%7D+%5C+%5Ctext%7Batau%7D+%5C+q+%3D++%5Csqrt%7B2p%7D+ "\displaystyle 1.) \frac{2p}{q} = \sqrt[3]{p^3q^6} : \sqrt{(pq)^2} \\ \frac{2p}{q} = pq^2 : pq \\ \frac{2p}{q} = q \\ 2p = q^2 \\ p = \frac{q^2}{2} \ \text{atau} \ q = \sqrt{2p}")
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Asruul
p = 1/2 q^2 atau p = q^2/2...?
RonaldRobi
sama aja
RonaldRobi
tapi biasanya sih penulisannya 1/2 q^2
Asruul
oo... thanks ya
RonaldRobi
yo , maaf gk bisa no 2 :v
Asruul
gpp...
Asruul
yang paling dibutuhkan no 1
RonaldRobi
oh ya ya
Asruul
sekali lagi thanks
RonaldRobi
ya sama sama
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