2 (3x+4) -5 (x+6) < 20=5
3(x-1) -4 (x-2) ≥ 6(x-3) - (x-4) - 4(x-2)=9
2(x+3) + 5(x-2) ≤ 2x-1 -2(x-3)=4
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
2 (3x+4) -5 (x+6) < 20=5
3(x-1) -4 (x-2) ≥ 6(x-3) - (x-4) - 4(x-2)=9
2(x+3) + 5(x-2) ≤ 2x-1 -2(x-3)=4