espero te ayude
salu2 desde Colombia
[tex]x^{2} -7 x = 0[/tex]
pasos:
[tex]\sqrt{(-7)^{2} -4*1*0} =7\\\\x_{1,2} =\frac{-(-7)+7}{2*1} ,x_{2} =\frac{-(-7)+7}{2*1}\\\\x=\frac{-(-7)+7}{2*1}:0[/tex]
solución:
[tex]x=7,x=0[/tex]
me das corona porfa
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
espero te ayude
salu2 desde Colombia
[tex]x^{2} -7 x = 0[/tex]
pasos:
[tex]\sqrt{(-7)^{2} -4*1*0} =7\\\\x_{1,2} =\frac{-(-7)+7}{2*1} ,x_{2} =\frac{-(-7)+7}{2*1}\\\\x=\frac{-(-7)+7}{2*1}:0[/tex]
solución:
[tex]x=7,x=0[/tex]
me das corona porfa